Question

(viii) kx +tx+1=0; x = 0.2, x = 0​

Answer 1

Answer:

The value (s) of k for which the quadratic equation kx^2 - kx + 1 = 0 has equal roots is

Step-by-step explanation:

kx^2 - kx + 1 = 0 It has equal roots, D = 0 ( - k)^2 - 4(k)(1) = 0 k^2 - 4k = 0 k(k - 4) = 0 k = 0 or k = 4 k≠ 0 For k = 0 , equation will not be quadratic