(viii) x - 4x² - x + 1 = (x - 2)3
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Answered by
5
Answer:
(viii) x³ – 4x² – x + 1 = (x – 2)³
x³ - 4x² - x + 1 = x³ - 8 - 6x² + 12x
x³ - 4x² - x + 1 - x³ + 8 + 6x² - 12x = 0
2x² - 13x + 9 = 0
It is the form of ax² + bx + c = 0
So, it is a quadratic equation.
ok
Answered by
2
Answer:
x-4x-x+1=(x-2)3
বা,x-3x+1=3x-6
বা,x+7=6x
বা,7=6x-x
বা,7=5x
~x=7/5
Step-by-step explanation:
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