Question

Vijay had some bananas, and he divided them into two lots A and B ,He sold the first lot
A at the rate of₹ 2 for 3 bananas and the second lot B at the rate of ₹ 1 per banana, and
got a total collection of ₹ 400. If he had sold the first lot A at the rate of ₹ 1 per banana,
and the second lot B at the rate of ₹4 for 5 bananas, his total collection would have been
₹2460
Determine the total number of bananas he had.
​

Answer 1

let x be the banana present in lot A

and y in lot B.

As per question,

3 bananas= ₹2

1 banana= ₹2/3

2/3 × x+y=400

(2x+3y)/3=400

2x+3y=1200

2x=1200-3y

x= (1200-3y)/2 (1)

And again if he had changed the price,

1 banana in lot A(x)= ₹1

5 banana in lot B(y)= ₹4

1 banana= ₹4/5

x+ 4/5 ×y = 2460

(5x+4y)/5= 2460

5x+4y= 12300

Putting the value of x

5(1200-3y)/2 +4y= 12300

(6000-15y + 8y)/2 = 12300

6000-7y= 24600

-7y= 24600-6000

y= 18600/7 = 2655

can you please recheck the question..