Math, asked by qazwsxedcr7034, 1 year ago

Vijay had some bananas and he divided them into two nodes A and B he saw all the first lot at the rate of 2 for 3 bananas and the second law and rate of 1 per banana and got a total of 400 if he had sold the first lot at the rate of 1 per banana and the second load at the rate of 4 for 5 banana his collection would have been for 60 find the total number of Bananas he has

Answers

Answered by amitnrw
168

Answer:

500 Bananas

Step-by-step explanation:

Let Say node A  has  A bananas

& Node B  has  B bananas

Amount received = 2A/3   + B = 400

=> 2A + 3B = 1200  - eq 1

A + 4B/5  = 460

=> 5A + 4B = 2300   - eq 2

3* eq2 - 4 * eq 1

=>  15A - 8A = 6900 - 4800

=> 7A = 2100

=> A = 300

2* 300 + 3B = 1200

=> B = 200

Total Bananas = 300 + 200 = 500

Answered by sahatrupti21
7

Answer:500 BananasStep-by-step explanation:Let Say node A  has  A bananas& Node B  has  B bananasAmount received = 2A/3   + B = 400=> 2A + 3B = 1200   - eq 1A + 4B/5  = 460=> 5A + 4B = 2300   - eq 2 3* eq2 - 4 * eq 1=>  15A - 8A = 6900 - 4800=> 7A = 2100=> A = 3002* 300 + 3B = 1200=> B = 200Total Bananas = 300 + 200 = 500

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