Question

vijay is a photographer for a newspaper and was editing an image for an article he cropped out a square from a photo .he tripled the width of the image but kept it square. He then cut off two rectangles from both sides of the image .the width of the image was now 2/3 of the width before this edit. then reduce the dimentions of the image by half.the area of the image was now 2166cm^2 .What was the area of initial cropped image?​

Answer 1

Answer:

newspaper and was editing an image for an article he cropped out a square from a photo .he tripled the width of the image but kept it square. He then cut off two rectangles from both sides of the image .the width of the image was now 2/3 of the width before this edit. then reduce the dimentions of the image by half.the area of the image was now 2166cm^2 .What was the area of initial cropped image?

Answer 2

The area of initial cropped image is 1422 $cm^{2}$.

Step-by-step explanation:

Let the side of the square image which is cut from the article be 'x'.

Now, according to question, the width of the square is tripled while remaining it square which means other side has also triples.

So, now side of square is '3x'.

Two triangles have been cut off which reduces the width to '2x'.

now, at last, the image is reduced by half which means that the side are also reduced by half.

So,

           New sides of squares,

                                    = $\frac{3x}{2} \times x$

According to question,

                                    ⇒ $\frac{3x}{2} \times x$ = 2166

      So,                         ⇒ $x^{2}$ = 1422  $cm^{2}$

This is the area of original image.