Math, asked by AmmuShivani4595, 1 year ago

Vijay is older than his sister seema by 12 years. 4 years ago vijay was 4 times as old as his sister. Find their present ages

Answers

Answered by uvy
0

Step-by-step explanation:

Vijay Seema(present)

Diff of age=12yr

4 years ago

Vijay Seema

4x x

Diff=3x=12 (ciz Diff of age ll always be same)

X=4

Vijay Seema(4yr ago)

4×4=16 4×1=4

Present ages of Vijay =16+4=20 Seema=4+4=8

Answered by Anonymous
4

Answer:

{\boxed{\bold{Seema= 16}}}

{\boxed{\bold{Vijay = 28}}}

Step-by-step explanation:

Given:-

⇢ Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister.

Find:-

⇢ Find their present ages.

Calculations :-

Let x be age of Seema and x + 12 be age of Vijay.

Four years ago:-

\rm{Seema = x - 4}

\rm{Vijay = x + 12 - 4 = 8}

Finding seema's age:-

\rm{2(x - 4) = x + 8}

\rm{2x - 8 = x + 8}

\rm{2x - x = 8 + 8}

{\boxed{\bold{x = 16}}}

Therefore, we know that 16 is the age of seema using seema's age we can find the age present age of Vijay.

\rm{x + 12}

\rm{16 + 12}

{\boxed{\bold{28}}}

ㅤ ㅤ ㅤ ㅤ ㅤ ㅤ

Therefore, 28 is the present age of Vijay.

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