Question

Vijay is older than his sister Seema by 12 years . Four years ago, Vijay was four times as old as his sister.Find their ages.

Answer 1

let the Seema age =x
then Vijay age =(x+12)
four years ago their ages are
Vijay age=(x+12-4)
seema age =4(x-4) =4x-16
the equation will be =(x+12-4)=4x-16
'""""""""""""""""""""""""=x+8=4x-16
“""""""""""""""""""""""""8+16=4x-x
"""""""""""""""""""""""""24=3x
"""""""""""""""""""""""""24/3=x
"""""""""""""""""""""""""8=x

Answer 2

Answer:

⇢ ${\boxed{\bold{Seema= 16}}}$

⇢ ${\boxed{\bold{Vijay = 28}}}$

Step-by-step explanation:

Given:-

⇢ Vijay is older then his sister seema by 12 years. Four year ago, Vijay was four times as old as his sister.

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Find:-

⇢ Find their present ages.

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Calculations :-

Let x be age of Seema and x + 12 be age of Vijay.

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Four years ago:-

⇢ $\rm{Seema = x - 4}$

⇢ $\rm{Vijay = x + 12 - 4 = 8}$

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Finding seema's age:-

⇢ $\rm{2(x - 4) = x + 8}$

⇢ $\rm{2x - 8 = x + 8}$

⇢ $\rm{2x - x = 8 + 8}$

⇢ ${\boxed{\bold{x = 16}}}$

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Therefore, we know that 16 is the age of seema using seema's age we can find the age present age of Vijay.

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⇢ $\rm{x + 12}$

⇢ $\rm{16 + 12}$

⇢ ${\boxed{\bold{28}}}$

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Therefore, 28 is the present age of Vijay.