Math, asked by rehana, 1 year ago

vijay obtains a loan of 64000rs against his fixed deposits.if the rate of interest be 2.5 paise per rupee per annum.what is the compound interest payable after 3 years.
1.4921rs
2.3925rs
3.5052rs
4.4573rs

Answers

Answered by praveensingh8344
18
CI = 64000*(1+ 2.5/100)^3 - 64000
    = 64000*41*41*41/(40*40*40) - 64000
  = 4921
Answered by tanmaytaylor6
0

Answer:

4921

Step-by-step explanation:

CI = 64000*(1+ 2.5/100)^3 - 64000

   = 64000*41*41*41/(40*40*40) - 64000

 = 4921

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