Question

Viji is twice as old as his brother Deepu. If the difference of
their ages is 11 years, find their present age.​

Answer 1

Answer :-

• Deepu is 11 years old.
• Viji is 22 years old.

Given :-

• Viji is twice as old as his brother Deepu.
• The difference of their ages is 11 years.

To find :-

• Their present age.

Step-by-step explanation :-

• Let Deepu's age be x.

• Since Viji is twice as old as his brother Deepu, therefore Viji's age will be 2x.

• It has been given that the difference of their ages is 11 years.

• It means that the difference of 2x and x is 11 years.

---------------------

$\sf \longmapsto 2x - x = 11$

Subtracting x from 2x,

$\longmapsto\underline{\boxed{\sf x = 11}}$

• The value of x is 11.

---------------------

Hence, their present ages are as follows :-

$\bf Deepu = x = 11$

$\bf Viji = 2x = 2 \times 11 = 22.$

Answer 2

Given :

• Viji is twice as old as his brother Deepu.
• The difference of their ages is 11 years .

To find :

• Present age.

Solution :

Let ,

The age of Deepu = x

The age of Viji = 2x

In the given question ,

Difference of their ages will be 11 years.

Now ,

We need to know that each

$\;\;\bf{\;\;\red{ = = ) \: 2x - 1 = 11}}$

$\;\;\bf{\;\;\blue{x\;=11}}$

Thus, age of Deepu is 11 years.

Thus ,

Age of Viji is

$\;\;\bf{\;\;\green{2x = 2 \times 11 = 22 \: years}}$