Question

vikas is three years older than deepika. 6 years ago, Vikas 's age was 4 times deepika's age. find the ages of deepika and vikas​

Answer 1

Answer:

Step-by-step explanation:

Given :-

Vikas is three years older than Deepika.

6 years ago, Vikas 's age was 4 times Deepika's age.

To Find :-

Ages of both.

Solution :-

let the age of Deepika be x  years.

And the age of vikas be x + 3 years.

6 years ago

Deepika's age = x - 6 years

Vikas's age = x + 3 - 6 = x - 3 years

As per the Question,

⇒ x - 3 = 4 (x - 6)

⇒ x - 3 = 4x - 24

⇒ x - 4x = -24 + 3

⇒ -3x = -21

⇒ 3x = 21

⇒ x = 21/3

⇒ x = 7

Deepika's age = x = 7 years

Vikas's age = x + 3 = 7 + 3 = 10 years.

Answer 2

$\mathfrak\red{\underline{Answer:Deepika=\:7\:years\:; Vikas=10\:years}}$

$\rule{100}2$

$\textbf{\underline{\underline{Step-By-Step\:Explanation:-}}}$

Let Deepika's age be ' D ' years. So, Vikas will be ' D + 3 '  because Vikas is 3 years older than her.

                   Six years ago,

• Deepika = D - 6
• Vikas = D + 3  - 6 = D - 3

According to question :

D - 3 = 4 ( D - 6 )

⇒ D - 3 = 4D - 24

⇒ D - 4D = - 24 + 3

⇒ - 3D = - 21

$\sf\implies {D} = \dfrac{-21}{-3} \\\\ \sf \therefore {D} = 7$

Finally,

Substitute the value of D in the variables.

Age of Deepika = 7 years.

Age of Vikas = 7 + 3 = 10 years.

$\rule{200}2$