Question

Vikas is three years older than Deepika. Six years ago, Vikas's age was four times
Deepika's age. Find the ages of Deepika and Vikas.​

Answer 1

★ Given Information

Vikas is three years older than Dipika. Six, years ago, Vikas's age was four times Deepika's age.

We're requested to find the ages of Deepika and Vikas.

So, Let

• Present age of Deepika = x years
• Present age of Vikas = (x + 3) years

★ Six years ago

• Age of Deepika = (x - 6) years
• Age of Vikas = (x + 3) - 6 = (x - 3) years

★ Now, according to question

➥ (x - 3) = 4 (x - 6)

➥ x - 3 = 4x - 24

➥ 4x - x = 24 - 3

➥ 3x = 21

➥ x = 21/3

➥ x = 7

★ Put the values

• Age of Deepika = x => 7 years
• Age of Vikas = x + 3 = 7 + 3 => 10 years

Hence, the ages of Deepika and Vikas are 7 years and 10 years respectively.

Answer 2

Answer:

★ Age of Deepika= 7 years

★ Age of Vikas = 7 years

Step-by-step explanation:

Given information

★Vikas is three years older than Deepika. Six years ago, Vikas's age was four times Deepika's age.

now we have to find the age of Deepika and Vikas

=> present age of Deepika=x years

=> present age of Vikas = (x+3)years

six years ago

Age of Deepika = (x-6) years.

Age of Vikas = ( x+3-6) years

according to the question

=> (x-3) = 4(x-6)

=> x-3 = 4x-24

=> 4x - x =24-3

=> 3x=21

$x = \frac{21}{3}$

=>x=7

put the values

=>Age of Deepika=x

x=7years

=>Age of Vikas= x+3

=7+3=10

hope it's help you ☺️☺️☝️☝️✍️✍️✍️