Math, asked by dakshtiwari1, 1 year ago

vikas is three years older that deepika. six years ago, vikas age was four times deepika age. find are of vikas ans deepika


Answers

Answered by TheLostMonk
9
let present age of Vikas be x and present age of deepika be y .

x = y + 3 ---(1)


6 years ago:


age of Vikas = y + 3 - 6 = y - 3

age of deepika = y - 6


since, 6 years ago age of Vikas was 4 times the age of deepika

so then,

y - 3 = 4 × ( y - 6)



y - 3 = 4y - 24


3y = 21 => y = 7 yrs


age of deepika y = 7 yr


age of Vikas = y + 3 = 7 + 3 = 10yrs

dakshtiwari1: thanks
TheLostMonk: WELCOME :)
Answered by shreeya8
2

Answer:


Step-by-step explanation:

present age of Vikas be x and present age of deepika be y .


x = y + 3 ---(1)



6 years ago:



age of Vikas = y + 3 - 6 = y - 3


age of deepika = y - 6



since, 6 years ago age of Vikas was 4 times the age of deepika


so then,


y - 3 = 4 × ( y - 6)




y - 3 = 4y - 24



3y = 21 => y = 7 yrs



age of deepika y = 7 yr



age of Vikas = y + 3 = 7 + 3 = 10yrs


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