vikas started to move to the north and covered 15m. he then turned right and moved 25m. after this he turned to his right and moved 35m. now how far is he from his starting point?
Answers
Answer:
Vikas started to move in the north and moved 15 m. Then he turned to his
right and moved 25 m. After this he turned to his right and moved 35 m.
Now how far is he from his starting position ?
15 m
Answer:
The distance from the starting point of vikas is 32.0156 meters.
Step-by-step explanation:
From the following figure, Let, A be the starting position of Vikas, and distance covered by Vikas while moving to north is 15 m (Distance from A to B) after he take right turn and cover 25 m (Distance from B to C) after it he take right turn again and cover 35 m (Distance from C to E)
where,
Distance AB = 15 m in north
Distance BC = 25 m in right turn
Distance CE = 35 m in right turn
Let, AB be perpendicular to BC and BC Perpendicular to CE.
- Construction of the ABCD:
- Let us consider, the following steps to be followed for constructing:
Draw AD which is parallel to BC and AD perpendicular to AB and CD (CE) and connect AE.
From the construction AE is known to be hypotenuse.
From figure, we can assume that
ABCD will be following the properties of rectangle.
Hence,
AB = CD = 15 m
BC = AD = 25 m
Again,
CE = CD + DE
DE = CE - CD
DE = 35 - 15
DE = 20 m
By applying the pythagoras's theorem,
let us find the position of vikas from his starting position,
(AE)² = (AD)² + (DE)²
(AE)² = (25)² + (20)²
(AE)² = 625 + 400
(AE)² = 1025
AE = √1025
AE = 5√41 m
Now, by evaluating the square root, we get,
32.0156 meters.
Therefore, the distance of the starting point he has reached is 32.0156 meters.
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