Question

. Viki thinks for three such numbers such that first is twice the second and is half of the third and
the average of three numbers is 56. Find the numbers in the same order.​

Answer 1

Answer:

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Step-by-step explanation:

Let the first number be x and y be the second number and z be the third number

given that, x = 2.y and x = z/2

Then, Second number(y) =

2

x

Third number(z) =2x

Given,

3x+ x+2x

=56⇒ 67x

=56⇒x= 756×648

∴ Difference between first and third =2x−x=x=48.