Math, asked by chaitanyasharma446, 18 days ago

Vikram and Vinay can do a work in 20 days together. They started the work together but after 8 days, alone in 30 days, then in how many days could he do the remaining work ?

Answers

Answered by devbpillai07
2

Answer:

Step-by-step explanation:

Since Vikram and Vinay can do a work in 20 days together

So their one day work =  1/20

Vinay can do the whole work alone in 30 days

so Vinay's one day work =  1/30

They worked together for 8 days so

work done by them in 8 days =  1/20* 8

                                                =  2/5 unit

remaining work =  1 - 2/5 =  3/5

Remaining work done by Vinay =  Remaining work/efficiency

                                                    =  3/5÷1/30

                                                    =  3/5*30

                                                    = 18 days

Step-by-step explanation:

Similar questions