Question

vimal mixes water and milk such that the solution of 40 litres of milk and water contains 10%
water. How much more water should be added in the solution so that there is 20% of water
in the new solution?​

Answer 1

Answer:

milk in Soln=40x90/,100 = 36 litre

New soln:=xlitre

Xx80/100 = 36

X = 3600/80=45 litre

Added water =45-40=5 litre

Answer 2

Answer:

Vimal needs to add 5 more litres of water

Step-by-step explanation:

The existing solution of milk and water is 40 litres and has 10 per cent water.

Hence, the volume of water is 10% of 40 litres = 4 litres.

Let "x" be the volume of water to be added.

According to the question, we have:

4 + x = 20% of (40 + x)

New quantity of water which is (4 + x) should be 20% of the new overall volume of the mixture, which is (40 + x)

=> 4 + x = 0.2*(40 + x)

=> 4 + x = 8 + 0.2x

=> x - 0.2x = 8 - 4

=>  0.8x = 4

=> x = 4/0.8

=> x = 5

Verify:

If 5 litres of water is added, the volume of the water becomes 9 litres and the total volume of the mixture becomes 45 litres. 9 is 20% of 45, which is what the sum expects.