Question

vina has$ 4.70 in quarters, dimes and nickles in purse.she has 8 more dimes than quarter and 6 more nickles than quarters . how many each coin are in purse​

Answer 1

Answer:

Step-by-step explanation:

$\sf{Required \ Answer}$

Given that :-

Total Dollars Vina has is $4.70

There are some quantity in form of Dimes, Nickles and Quarters as well.

We need to find the number of coins there.

So, here we go with the basic concept that the value of Quarter is 0.25, Nickles is 0.05 and Dimes is 0.10

Let the number of Quarters be x.

So, Dimes will be 8 + x.

And nickles 6 + x.

Now, forming the equation:-

0.10(8+x) + 0.05(6+x) + 0.25(x) = 4.70

0.8 + 0.10x + 0.3 + 0.05x + 0.25x = 4.70

1.1 + 0.4x = 4.7

0.4x = 3.6

x = $\dfrac{3.6}{0.4}$

x = 9 coins. Quarters]

So, 6+x = 6+9 = 15 coins Nickles]

8+x = 8+9 = 17 coins Dines]

Answer 2

Answer:

Given :-

Total Dollars Vina has is $4.70

There are some quantity in form of Dimes, Nickles and Quarters as well.

To Find :-

Each coin in purse

Solution :-

Let the number of quater be y

Dimes will be 8 + y.

And nickles 6 + y.

Now,

0.10(8+ y) + 0.05(6+y) + 0.25(y) = 4.70

0.8 + 0.10y + 0.3 + 0.05y + 0.25y = 4.70

1.1 + 0.10y + 0.05y + 0.25y

1.1 + 0.4y = 4.7

0.4y = 4.7 - 1.1

0.4y = 3.6

y = 9

Dimes = 17

Nickles = 15

Quater = 9