Vinay bought a pizza and cut it into three pieces. When he weighed the first piece he found that it was 7g lighter than the second piece and 4g heavier than the third piece. If whole pizza weighed 300g.How much did each of the three pieces weigh.
Answers
Answered by
433
Let the weight of the 1st piece =xg
Let the weight of the 2nd piece=(x+7)g
Let the weight of the 3rd piece =(x-4)g
Total weight of pizza =300g
xg +x+7g+x-4g =300g
3x+3 =300g
3x =300g-3
x =297g/3
x =99g
So, the weight of the pieces
1st piece = x =99g
2nd piece =x+7=99+7=106g
3rd piece =x-4 =99-4 =95g
Ans.=The weight of the three pieces of pizza are 99g, 106g and 95g.
Let the weight of the 2nd piece=(x+7)g
Let the weight of the 3rd piece =(x-4)g
Total weight of pizza =300g
xg +x+7g+x-4g =300g
3x+3 =300g
3x =300g-3
x =297g/3
x =99g
So, the weight of the pieces
1st piece = x =99g
2nd piece =x+7=99+7=106g
3rd piece =x-4 =99-4 =95g
Ans.=The weight of the three pieces of pizza are 99g, 106g and 95g.
Answered by
165
Hey there '_^
Weight of third piece to be considered
" x "
then, TheWeight of First one Pizza piece = x +4
Then second pizza piece = first piece + Weight less /more
= (x +4)+ 7
= x + 11
Given Total weight = 300 g
x + x + 4 + x + 11 = 300
3x = 300-15
x = 285/3
x = 95
Therefore, Weight of
1) 1st Piece = x +4 = 95 +4 = 99
2) 2 nd Piece = x + 11 = 95 +11 = 106
3) 3 rd piece = x = 95
hope helped!
Weight of third piece to be considered
" x "
then, TheWeight of First one Pizza piece = x +4
Then second pizza piece = first piece + Weight less /more
= (x +4)+ 7
= x + 11
Given Total weight = 300 g
x + x + 4 + x + 11 = 300
3x = 300-15
x = 285/3
x = 95
Therefore, Weight of
1) 1st Piece = x +4 = 95 +4 = 99
2) 2 nd Piece = x + 11 = 95 +11 = 106
3) 3 rd piece = x = 95
hope helped!
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