Question

Vinay runs twice a rectangular fied with length 180m and breadth 110m. What distance does he cover.

Answer 1

Heya dear user !!!

Here is your answer,

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Given : -
length of rectangular field = 180m
breadth of rectangular field = 110m

Vinay runs on the boundary of the rectangular field (perimeter of the rectangular field)

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Perimeter of the rectangular field
= 2(l+b)

= 2(180+110)

= 2×290

= 580m

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According to the question
Vinay runs twice (two times) the rectangular field.

So, the total distance covered by Vinay = 2×580

= 1160m

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Hope it helps.

Answer 2

Given :-
Length = 180m
Breath = 110m
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The distance Varun covers in one round will be the length of the perimeter
=> The length in two rounds will be twice the perimeter
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Perimeter = 2 ( L × B )
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Here L is the length of the rectangular field and B is its breath.

Distance covered by Varun = 2 × perimeter

= 4( 180 + 110 )m

= (4 × 290)m

= 1160m

Hence the distance covered by Varun in two rounds is 1160 meters.