Math, asked by ishaan2399, 3 months ago

Vinay's age is 3 times his son's age. 6 years ago, he was 5 times his son's age. Find their present ages.​

Answers

Answered by gauravgpt
1

Answer:

Let vinay's son age =x

vinay's age =3x

Ten years ago, he was 5 times the age of his son.

Therefore, 3x−10=5(x−10)

3x−10=5x−50

2x=40

x=20

vinay's son is 20 yrs old

vinay is 3x=3×20=60 yrs old

Answered by varunrawat43
1

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