Question

vinaya scored 10 marks more in second test than that of first test. five times the score of the second is the same as square of the score in her first test . find her score in first test ​

Answer 1

Answer:

10

Step-by-step explanation:

let score be x

marks in 2nd test x+10

5(x+10)= x'2

5x+50=x'2

x'2-5x-50

By splitting middle term

x'2-10x+5x-50

x(×-10)+5(x-10)

So,

(x+5) OR (x -10)

x=-5 Or x=10

Marks can't be negative so x=10

Score in first test is 10

Answer 2

Answer:

Step-by-step explanation:

let score of first test x and that of second be y

ATTQ

y-x=10  (1)

y=10+x

5y=$x^2$ (2)

put the value of y in (2)

5(10+x) =$x^2$

50+5x=$x^2$

$x^2$-5x=50

x(x-5)=50

x =5 or x=55