Question

Vince went on a 3 day hiking trip. Each day, he walked 3/4the distance that he walked the day before. He walked 83.25 kilometers total in the trip. How far did Vince walk on the 1st day of the trip? Round your final answer to the nearest kilometer.

Answer 1

Answer:

1/4 of 83.25 kilometers

Answer 2

Vince traveled 36 km on first day

Solution:

Each day, he walked 3/4th distance that he walked the day before

Let "x" be the distance traveled on 1st day

Therefore,

$First\ day = x\\\\Second\ day = \frac{3}{4}x\\\\Third\ day = \frac{3}{4} \times \frac{3}{4}x = \frac{9}{16}x$

He walked 83.25 kilometers total in the trip

Therefore,

$x + \frac{3x}{4} + \frac{9x}{16} = 83.25\\\\16x + 12x + 9x = 83.25 \times 16\\\\37x = 1332\\\\x = 36$

Thus he traveled 36 km on first day

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