Math, asked by asthakushamwar, 2 months ago

Vineet borrows a sum of 3 50,000 at the rate of 10% p.a. for 6 years. Find the simple
interest that Vineet has to pay. Also calculate the amount to be paid after 6 years.​

Answers

Answered by madhuvanthikapradeep
0

Answer:

210000

Step-by-step explanation:

simple intrest = PRT/100

so

350000*10*6/100

100 cancels 10 and 1 zero in 350000

so we get 35000*6

= 210000

Answered by TwilightShine
26

Answer :-

  • Vineet has to pay Rs 210000 as simple interest.

  • The amount to be paid after 6 years is Rs 560000.

Given :-

  • Vineet borrows a sum of Rs 3,50,000 at the rate of 10% p.a. for 6 years.

To find :-

  • The simple interest that Vineet has to pay.

  • The amount to be paid after 6 years.

Step-by-step explanation :-

  • In this question, it has been given that Vineet borrows a sum of Rs 3,50,000 at the rate of 10% p.a. for 6 years. We have to find the simple interest that Vineet has to pay and also calculate the amount to be paid after 6 years.

  • The money borrowed by Vineet can be taken as the principal. We can take 10% as the rate and 6 years as the time. Now let's find the simple interest on Rs 3,50,000 at the rate of 10% p.a. for 6 years. It will be the simple interest that Vineet has to pay. We are going to do this using a formula.

Calculations :-

We know that :-

  \underline{\boxed{\sf SI =  \dfrac{Principal \times Rate \times Time}{100}}}

Here,

  • Principal = Rs 3,50,000.
  • Rate = 10% per annum.
  • Time = 6 years.

  \underline{\mathfrak{Substituting  \: these  \: values  \: in \:  this \:  formula,}}

  \boxed{\tt Simple \:  Interest =  \dfrac{3500 \!\!\!\not0 \!\!\!\not0 \times 10 \times 6}{1 \!\!\!\not0\!\!\! \not0}}

Cutting off the zeroes,

 \boxed{ \tt Simple \:  Interest =  \dfrac{3500 \times 10 \times 6}{1}}

Now let's multiply the remaining numbers, since we can't reduce them anymore.

  \boxed{\tt Simple \:  Interest = 3500 \times 10 \times 6}

On multiplying the numbers,

  \overline{\boxed{\tt Simple \:  Interest = Rs \: 210000.}}

  • So, Vineet has to pay Rs 2,10,000 as simple interest.

------------------------

  • Now, let's find the total amount to be paid after 6 years.

We know that :-

  \underline{\boxed{ \sf Amount = Principal + Interest.}}

Here,

  • Principal = Rs 3,50,000.
  • Interest = Rs 2,10,000.

Hence,

 \boxed{ \tt Amount = 350000 + 210000}

On adding the numbers,

  \overline{\boxed{ \tt Amount = Rs \: 560000.}}

  • So, the amount to be paid after 6 years is Rs 560000.
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