Vipul and Ajay are friends. Vipul is elder to Ajay by two years. Vipul's father is twice his son's age. Ajay is twice the age of his sister. If the ages of Vipul's father and Ajay's sister differ by 40 years, Find Vipul's and Ajay's age.
Answers
Answered by
1
x-y= 2
2X- Y/2 =40
Solve 1 and 2
26 = vipul
ajay= 24
Answered by
3
Answer :-
Let us assume that, Ajay age is x years .
so,
→ Vipul age = (x + 2) years .
then,
→ Vipul's father age = 2(x + 2)
→ Ajay sister age = half of ajay = (x/2)
A/q,
→ 2(x + 2) - (x/2) = 40
→ 4x + 8 - x = 80
→ 3x = 72
→ x = 24 years .
therefore,
- Ajay's age = x = 24 years .
- Vipul's age = (x + 2) = 24 + 2 = 26 years .
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