Question

Virat borrowed some money for 5 years at simple interest. The rate of interest is 9 p.c.p.a
If he returned 17.4 rupees altogether at the end of 5 years. How much had he borrowed?​

Answer 1

Given:

Virat borrowed some money for 5 years at simple interest. The rate of interest is 9 p.c.p.a If he returned 17.4 rupees altogether at the end of 5 years.

To find:

How much had he borrowed?​

Solution:

The formula simple interest to be used is:

$\bigstar\boxed{\bold{S.I. = \frac{P\times R \times T}{100} }}\\\\\bigstar\boxed{\bold{A = P + S.I.}}$

The no. of years, T = 5 years

The rate of interest, R = 9% p.a.

The amount that Virat had returned at the end of 5 years = Rs. 17.4

Let "P" represents the sum of money Virat had borrowed.

Now, by combining the two formulas above, we get

$A = P + \frac{P\times R \times T}{100}$

on substituting the given values of A, R & T, we get

$\implies 17.4 = P + \frac{P\times 9 \times 5}{100}$

$\implies 17.4 = \frac{100 P + 45P}{100}$

$\implies 1740 =100 P + 45P$

$\implies 1740 =145 P$

$\implies \bold{P = 12}$

Thus, Virat had borrowed → Rs. 12.

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Answer 2

Given :- Virat borrowed some money for 5 years at simple interest. The rate of interest is 9 p.c.p.a . If he returned 17.4 rupees altogether at the end of 5 years. How much had he borrowed ?

Answer :-

we know that, when rate is simple interest per annum ,

• Simple interest = (Principal * Rate * Time)/100
• Amount = Principal + Simple interest.

So, Let us assume that Principal is Rs.x .

then,

→ Principal + Simple interest = Amount

→ x + (x * 9 * 5)/100 = 17.4

→ x + (45x/100) = 17.4

→ x + (9x/20) = 17.4

→ (20x + 9x)/20 = 17.4

→ 29x = 17.4 * 20

→ 29x = 348

→ x = Rs.12 (Ans.)

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