Physics, asked by Gupta696, 1 year ago

Viscous drag proportional to $r$ or $r^3$?

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Answered by Anonymous
0
When a spherical object is falling at terminal velocity through a fluid: W=U+FW=U+F, where WW is weight, UU is upthrust and FF is viscous drag. Rewriting, using Stoke's Law, we get:

43πr3ρobject.g=43πr3ρfluid.g+6πrηvt43πr3ρobject.g=43πr3ρfluid.g+6πrηvt

6ηvt=43r2ρobject.g−43r2ρfluid.g6ηvt=43r2ρobject.g−43r2ρfluid.g

vt=2r2(ρobject−ρfluid).g9η,vt=2r2(ρobject−ρfluid).g9η,

where rr is the radius of the object, ρρ is density, ggis the gravitational acceleration, ηη is the viscosity coefficient, and vtvt is the terminal velocity of the object.

Answered by Anonymous
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