Chemistry, asked by ahnost07, 3 days ago

Vishal took 3 mL of potassium sulphate solution in a beaker and added approximately 3 mL of barium chloride solution. What would he observ:ed?

(a) Insoluble yellow precipitate was formed .

(b) Insoluble white precipitate was formed

(c) Insoluble green precipitate was formed ·

(d) The soluble become blue​

Answers

Answered by hirakvaru
6

Answer:

B -  Insoluble white precipitate was formed

Answered by AditiHegde
5

Vishal took 3 mL of potassium sulphate solution in a beaker and added approximately 3 mL of barium chloride solution.he observed that Insoluble white precipitate was formed.

  1. when potassium sulfate reacts with barium chloride , the product formed are barium sulfate and potassium chloride.
  2. an insoluble precipitate of barium sulfate is formed of white colour is formed.

equation-  BaCl2+K2So4 -----> BaSo4+ 2KCl.

the above equation is a balanced equation.

chemical equation is a process where two or more chemical substance reacts together to form another chemical compound.

Similar questions