Question

Visible light has wavelengths in the range of 400 nm to 780 nm. Calculate the range of energy of the photons of visible light.

Answer 1

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Answer 2

Answer:

2.55 * 10^-19 J to 5*10^-19 J

Explanation:

Given range of visible light = 400 nm to 780nm

Energy of photon is given as:

E = hv where, v= c/λ

here, c = 3*10^8 m/s and h = 6.63*10^-34 Js

Energy of photon of wavelength 400 nm:

E₁ = hc/λ = (6.63*10^-34 * 3*10^8) / (400*10^-9) ≈ 5*10^-19 J

Energy of photon of wavelength 780 nm:

E₂ = hc/λ = (6.63*10^-34 * 3*10^8) / (780*10^-9) ≈ 2.55*10^-19 J

Therefore range of Energy of photons of visible light is 2.55 * 10^-19 J to 5*10^-19 J.