Question

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Answer 1

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Answer 2

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Explanation:

Answer:

$s_{1} = 5 + 11 = 16 = first \: \: term \: \: of \: \:a .p. \\ \\ s_{2} = 5 \times 4 + 11 \times 2 = 20 + 22 = 42 \\ \\ = > common \: \: difference \: = 42 - 16 = 26 \\ \\ = > t_{n} = a + (n - 1)d \\ \\ = > t_{n} \: = 16 + (n - 1)26 = 26n - 10$