Question

Voices of swimmers at a pool travel 400 m/s through the air and 1,600 m/s underwater. The wavelength changes from 2 m in the air to 8 m underwater.

How has the change in media affected the frequency of the wave?

It increased.
It decreased.
It stayed the same.
It cannot be calculated.

Answer 1

Answer:

it is increased

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Answer 2

Answer:

The correct answer is it stayed the same.

Explanation:

In fact, the frequency of a wave is given by:

 

$f = v/\pi$

Applying the formula:

- In air, the frequency of the wave is:

$f = 400ms/2m = 200Hz$

200Hz

- underwater, the frequency of the wave is:

$f = 1600ms/8m= 200Hz$

200Hz

So, the frequency has not changed.