Question

void f(int *a, int m) {
int i=0;
for(j=0; j<m;j++X
*(a+j) = *(a+j)-5;
}
}
int main() {
int al = {'s', 'V', 'c', 'e'};
int i=0;
f(a, 4);
printf("%d\t", a[1] - 'a');
return 0;
}​

Answer 1

Answer:

-16

Explanation: