Question

void perform( int n)
int s=0,g;
while( n>0)
if (n%2=1)
n/=10;
g=n%10;
System.out.print("\n g = \t" + g);
s=s+g;
n/= 5;
System.out.print("\n s = \t" + s);​

please I need the answer fast
I will surely mark as brainliest
pleaseeeeee
​

Answer 1

Answer:

= 5;System.out.print("\n s = \t" + s);​...

Question 3 The following is a method/function of some class. Give the output of the

perform() when the value of 'n' is 6579. Show the dry run/ working.

void perform( int n)

int s=0,g;

while( n>0)

if (n%2=1)

n/=10;

g=n%10;

System.out.print("\n g = \t" + g);

s=s+g;

n/= 5;

System.out.print("\n s = \t" + s);​

Explanation: