Question

Volt is equal to
(A) coulomb / joule
(B) joule / coulomb
(C)
joule / ampere
(D)
ampere / joule​

Answer 1

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here is your answer

Volt is equal to ____

option (B)

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Answer 2

★ Provided Question ★

Volt is equal to

• (A) coulomb / joule
• (B) joule / coulomb
• (C) joule / ampere
• (D) ampere / joule

★ Required Answer ★

• (B) joule / coulomb

How?

We know that,

• $\sf { V = \dfrac{W}{Q} }$

Where,

✤ V is potential difference

✤ W is work done

✤ Q is charge

Also we know that:

• Si unit of potential difference (V) is volt(V).
• Si unit of work done(W) is joule(J).
• Si unit of charge (Q) is coulomb (C).

From these information we can conclude that-

• $\sf \red { V = \dfrac{W}{Q} \implies 1volt = \dfrac{1Joule}{1Coulomb}}$

Thus, correct option is option (B) which is Joule/Coulomb☑ .

Also we can say that:

• The potential difference between two points is said to be 1 volt if 1 joule of work is done in 1 coulomb of electric charge from one point to another.

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★ Let's Know More ★

Some important formulae with their SI units:-

• $\sf { V = \dfrac{W}{Q} }$

✤ V is potential difference and its SI unit is volt (V).

$\sf \red { 1volt = \dfrac{1Joule}{1Coulomb}}$

✤ W is work done and its SI unit is joule(J).

✤ Q is electric charge and its SI unit is coulomb(C).

• $\sf { I = \dfrac{Q}{t} }$

✤ I is electric current and its SI unit is ampere(A).

$\sf \red { 1Ampere = \dfrac{1Coulomb}{1second}}$

✤ Q is electric charge and its SI unit is coulomb (C).

✤ t is time and its SI unit is second(s).

• $\sf { V = IR }$

✤ V is potential difference and its SI unit is volt(V).

✤ I is electric current and its SI unit is ampere(A).

✤ R is resistance and its SI unit is Ohm.

• $\sf { R_s = R_1+R_2+R_3.....}$ (For Series combination of resistors.)
• $\sf { \dfrac{1}{R_p}= \dfrac{1}{R_1}+ \dfrac{1}{R_2} + \dfrac{1}{R_3}.....}$(For parallel combination or resistors).

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