Question

voltage applied across the coolidge tube is 25 KV what is kinetic energy of electron striking at the target and cutoff wavelength of X-Ray obtained from the tube​

Answer 1

kinetic energy = 4 × 10^-15 J and wavelength = 0.007737 nm

applied voltage across the Coolidge tube is 25kV

so, kinetic energy = charge of an electron × voltage

= e × 25kV

= 25keV

we know, 1eV = 1.6 × 10^-19 J

so, 25keV = 25 × 10³ × 1.6 × 10^-19 J

= 4 × 10^-15 J

hence, kinetic energy, E = 4 × 10^-15 J

wavelength = h/√(2mE)

here m is mass of electron and E is kinetic energy.

= 6.6 × 10^-34/√{2 × 9.1 × 10^-31 × 4 × 10^-15)

= 6.6 × 10^-34/√(2 × 9.1 × 4) × 10^-23

= 6.6 × 10^-11/8.53

= 0.7737 × 10^-11 m

= 0.007737 nm

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Answer 2

$\huge\bold\purple{Answer:-}$

kinetic energy = 4 × 10^-15 J and wavelength = 0.007737 nm

applied voltage across the Coolidge tube is 25kV

so, kinetic energy = charge of an electron × voltage

= e × 25kV

= 25keV

we know, 1eV = 1.6 × 10^-19 J

so, 25keV = 25 × 10³ × 1.6 × 10^-19 J

= 4 × 10^-15 J

hence, kinetic energy, E = 4 × 10^-15 J

wavelength = h/√(2mE)

here m is mass of electron and E is kinetic energy.

= 6.6 × 10^-34/√{2 × 9.1 × 10^-31 × 4 × 10^-15)

= 6.6 × 10^-34/√(2 × 9.1 × 4) × 10^-23

= 6.6 × 10^-11/8.53

= 0.7737 × 10^-11 m

= 0.007737 nm