Question

voltage is applied across points A and B ,so that current flows

from A , to R2, to B.What is the value of this voltage if the current

through R2 is 4A?(R1=3Ω , R2 = 2Ω )

2​

Answer 1

Answer:

the answer is 3.2Volt

please mark me as brain list

Answer 2

Answer:

3.2V

Explanation:

Given:

• R1 = 3Ω
• R2 = 2Ω
• I (total) = 4A
• V = 12V

To find:

• Voltage (V)

Solution:

First, we need to calculate the current flowing through R2 without the extra voltage attached. We will need to calculate the total equivalent resistance of the circuit. Since, the two resistors are in series, we can simply add them.

$R_{eq} = R1 + R2 = 3 + 2 = 5Ω$

Then, we can use Ohm's law to calculate the current through the circuit:

$V = IR$

$\: I \: = \frac{V}{R } = \frac{12}{5} = 2.4$

$I = 2.4A$

Now, that we have the current, we can calculate the additional current that the new voltage contributes:

$\:I _{total} = I + I_{new}$

$I_{new} = 4 - 2.4 = 1.6A$

There is only one resistor (R2) in the path of the new voltage, so we can calculate what that voltage needs to be to deliver the new current:

$V = IR2= 1.6 \times 2 = 3.2V$

Therefore, the value of this voltage if the current through R2 is 4A is 3.2V.

Formula Used:

• V = IR (Ohm's law)
• R(eq) = R1 + R2

Ohm's Law

Ohm's Law is a formula which is used to calculate the relationship between voltage, current and resistance in an electrical circuit. To the students of electronics, Ohm's Law (V = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists.

Ohm's Law Equation:

$V = IR$

Where,

• V is the voltage across the conductor.
• I is the current flowing through the conductor.
• R is the resistance provided by the conductor to the flow of current.

For more similar reference:

https://brainly.in/question/15587515

https://brainly.in/question/33532270

#SPJ3