Voltage of bulb 5 volt and current is 500 mamp. Find resistance , power and energy in 2.5 hour?
Answers
Answer:
For example:
A torch bulb is rated 5 V and 500 mA. Calculate (i) its power (i) resistance and (ii) energy consumed when it is lighted for 4 hours.
Answer:
Potential difference =V=5V
Current =I= 500mA=500x/1000 A=0.5 A
I) Power = V X I
= 5x0.5 =5x5/10=2.5 W
II)Reistance =R=?
By Ohm's law: V=IR
R=V/I
R=5/0.5
=50/5 =10 ohms
III)Energy consumed when it is lighted for 4 hours
Energy =Power x time
t=4hrs=4x60x60
=2.5x 4x60x60
=36000joules/sec
Now you may try to get the answer to your questionby referring to the example given below!!
Given ,
Potential difference (v) = 5 volt
Current (I) = 500 ma or 0.5 a
Time (t) = 2.5 h or 9000 sec
We know that ,
V = IR
Thus ,
5 = 0.5 × R
R = 5/0.5
R = 10 ohm
Electric power (P) = VI
Thus ,
P = 5 × 0.5
P = 2.5 watt
Electric energy = Power × Time
Thus ,
Electric energy = 2.5 × 9000
Electric energy = 22500 joule