Volume at ntp of oxygen required to burn 1kg of coal
Answers
Answered by
5
Answer:1866.66L
Explanation:
C + O2------>co2
1000g
Moles of c=1000/12
=83.33
Volume of c at ntp= 83.33*22.4 =1866L
1vol of c combine with 1vol of o2
1866L will combine with 1866L of O2
Answered by
2
Answer:
Mass of C = 1000 g
1 moles C requires 1 mole O₂ to burn.
Thus, 83.34 mole C requires 83.34 moles O₂
At NTP, 1 mole gas occupies 22.4 litres.
83.34 moles occupies 83.34 × 22.4 = 1.86 × 10³ L
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Explanation:
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