volume occupied by 20.050 g of chloroform is
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chloroform molecular formula = CHCl₃
molecular mass of chloroform= 12+1+35.5*3= 119.5g
119.5g of CHCl₃ in stp condition has 22.4l volume
20.050g has = 22.4l*119.5/20.050
=133.5L
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