Question

volume occupied by 28g N2 gas at STP

Answer 1

no of moles = given wt/molecular wt
here,
given wt = 28g
molecular wt of N2gas = 28 g/mol
no of moles = 28/28 = 1

volume of N2 gas at STP = no of mole × 22.4 L
= 1 × 22.4 L = 22.4 L

Answer 2

hi friend,

<>number of moles =given weight/molecular weight.

<>28/28=1

1 mole of N2 gas at STP always occupies 22.4 litres ..


I hope this will help u ;)