Volume occupied by 3.01 x 10^23 hydrogen molecules at STP
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0
Answer:
Answer. And one mole of a gas contain=6.02* 10^23 molecules. Thus the 3,01*10^23 of oxygen will have the volume of 11.2 liter.
Answered by
1
Answer:
1 mol = 6.022×10
23
3.01×10
23
=
6.022×10
23
3.01×10
23
=0.5moles
Hence, as per given, 0.5 moles of gas has mass = 20 grams.
So, 1 mol of gas has mass =2×20=40 grams.
Hence, we can say that this gas has molar mass = 40 gram/mole.
1 mole gas has 22.4 L volume at STP, hence, 0.5 moles of this gas 11.2 L volume.
Explanation:
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