Volume occupied by 30g of nitrogen at stp
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♧ Key
One mole of any gas occupies 22.4L volume
♧ Given
● Atomic mass of N =14
● Nitrogen gas is diatomic molecule
● Molecular mass of N2 = 28 gm
● Sample mass of N2 = 30 gm
◇ Number of mols equals sample mass divided over molecular mass
☆ n= 30÷28= 1.07 mol
☆ Volume = 1.07 × 22.4 = 24 L
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