volume occupied by 6.023 into 10^22 molecules of NH3
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Volume occupied by 1 Mole of a gas that is 6.023 * 10^23 is 22.4 L.
So foe 6.023 * 10^ 22 molecules will be 22.4/10= 2.24 L
So foe 6.023 * 10^ 22 molecules will be 22.4/10= 2.24 L
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