Volume occupied by 8gm of oxygen at stp
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8gm oxygen will occupy 11.2 L volume at STP
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Molecular weight of oxygen = 32 g
32 g of oxygen occupies 22.4 L volume at STP
8 g of oxygen will occupy volume = (8 × 22.4) / 32 = 5.6 L
∴ Volume occupied by 8 g of oxygen at STP is 5.6 litres
32 g of oxygen occupies 22.4 L volume at STP
8 g of oxygen will occupy volume = (8 × 22.4) / 32 = 5.6 L
∴ Volume occupied by 8 g of oxygen at STP is 5.6 litres
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