Question

Volume occupied by 8gm of oxygen at stp

Answer 1

8gm oxygen will occupy 11.2 L volume at STP

Answer 2

Molecular weight of oxygen = 32 g

32 g of oxygen occupies 22.4 L volume at STP
8 g of oxygen will occupy volume = (8 × 22.4) / 32 = 5.6 L

∴ Volume occupied by 8 g of oxygen at STP is 5.6 litres