Chemistry, asked by anu842, 10 months ago

Volume occupied by one molecule of water
(density = 1 g cm-3) is
(1) 5.5 * 10-23 cm
(2) 9.0 x 10-23 cm3
(3) 6.023 * 10-23 cm3
(4) 3.0 * 10-23 cm3

Answers

Answered by YaminiRathi
46

density = mass/volume

volume=mass/density

=1 gram/ 1 gram cm⁻³ = 1 cm³

1 g water= 1/18 moles of water

(at wt of H *2 + at wt of oxygen = 18)

volume occupied by 1 molecules of water = (18 / (6.02 x 10²³)) cm³

= 3 x 10⁻²³ cm³


mansisivach14: how come you divided the molecular weight of H2O with avagadro's no.??
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