Question

volume occupied by one molecule of water is how much?
(density =1 h cm^-3)

Answer 1

Hi friend here is your answer

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One molecule of water has Molecules equal to Avogadro number which has mass 18 g

So mass of one molecule

= 18 / 6.022 * 10^23

=2.98 * 10^-23


Density = mass / volume

Volume = mass of 1g of water/density

= 2.98*10^-23/10^-3

= 2.98*10^-20


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Hope it helps you......!! ________________________________ TheUsos


Down since Day One Ish

Answer 2

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