Chemistry, asked by ZID, 10 months ago

Volume of 0.1M HCL required to make 5L of 0.01 M HCL solution is

Answers

Answered by AditRC
5
V1 S1 = V2 S2
0.1 V1 =5 * 0.01
V1 = 0.05/ 0.1
V1 = 0.5L
Answered by roopiniP
2

N1V1=N1V2

0.1×V1=0.01×5

0.1×V1=0.05

V1=0.5lit

hope the answer is helpful.

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