Question

Volume of 0.44g of carbon dioxide at S.T.P is- a)22.4L b)2.24L c)0.224L d)0.0224L​

Answer 1

Correct option is

B

2.24 L

As given,

Mole =

Molar mass

mass

=

44

4.4

=0.1

V

CO

2

=n×Molar volume=0.1×22.4=2.24 L

Hence, the correct option is B

Hope it helps ❤️