Question

Volume of 0.5 M NaOH solution required for complete
neutralisation of 3.65 g HCl is​

Answer 1

Answer:

0.2L

Explanation:

moles of NaOH= V×M=V×0.5 ... (i)

moles of HCL= w/MW= 3.65/36.5=0.1 ...(ii)

equating i and ii

V×0.5=0.1

V=0.2 L

Answer 2

Answer:

0.2 L or 200 ml

Explanation:

>>for neutralisation-

no. of moles of NaOH should be equal to no. of moles of HCL

>>no. of moles of HCL=3.65/36.5=0.1moles

>>no. of moles of NaOH=0.1

molarity(M)=no. of moles of solute/volume of solution(in L)

>>0.5=0.1/vol. of solution

>>vol. of solution=0.1/0.5

=1/5

=0.2 L or 200 ml