Chemistry, asked by zairashahid37061, 4 days ago

Volume of 1.6 grams of O2 at STP

Answers

Answered by jenilp137

0

Answer:

1 mole of a gas occupy =22.4L volume at STP therefore, 16gO2 gas =0.5 mole of O2 gas will occupy =0.5×22.41=11.2L at STP.

Explanation:

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