Question

Volume of 1.7 g NH3 gas at 1 atm and 0°C is :-
22.4 L
2.24 L
22.4 mL
2.24 mL
​

Answer 1

Explanation:

mass of 1 mole of NH3:-

(14×1)+(1×3) = 17grams

now 1.7 grams of NH3 is one tenth of 1 mole of NH3 gas.

volume of 1 mole of NH3= 22.4litres

volume of 1\10th of mole of NH3=2.24 litres

Hope it helps..

Answer 2

Explanation:

Let us first calculate number of moles of NH3 in 1.7 g NH3 sample.

We know that,

$\underline{\boxed{\sf Moles = \dfrac{Given\:mass}{molar \:mass}}}$

$\sf Given \: mass \: of \: NH_3 = 1.7 g$

$\sf Molar \: mass \: of \: NH_3 = 14+3=17\:g$

$\sf Moles \: of \: NH_3 = \dfrac{1.7}{17} = 0.1 \: moles$

We know that,

$\underline{\boxed{\sf moles = \dfrac{Volume \:(in \:litres)}{22.4}}}$

$\sf 0.1 = \dfrac{Volume \: of \: NH_3}{22.4}$

$\sf Volume \: of \: NH_3 = 22.4×0.1 = 2.24 \: litres$

Hence, option (B) 2.24 L is coorrect